An interesting problem I ran across on a blog the other day. Quote from the blog….

Given a function which produces a random integer in the range of 1 to 5, write a function which produces a random integer in the range of 1 to 7

This is well-known as one of the so called Microsoft/Google interview questions. There are million ways to solve it.

So here is my Take on the solution.

| ```
int rand7() {return 7 / rand5();}
``` |

You will only get 1 2 3 or 7 using this solution, but the requirements didn’t call for uniformity. More uniform would be

| ```
int rand7() {return (( rand5() + rand5() ) % 7) + 1;}
``` |

A friend of mine was confused with the modulus ‘%’ in this function. The modulus returns the remainder of a division operation. The remainder of a division can never be greater than the dividing number ( in this case 7 ) which means % will always return a number between 6 and 0 ( 0 … 6 ) which is also why we add a +1 to the result to get 1 thru 7